/*
 * Simple Ajax call method.
 *
 * From http://en.wikipedia.org/wiki/XMLHttpRequest
 */
function ajax(url, vars, callbackFunction) {
  var request =  new XMLHttpRequest();
  request.open("POST", url, true);
  request.setRequestHeader("Content-Type",
                           "application/x-www-form-urlencoded");

  request.onreadystatechange = function() {
    if (request.readyState == 4 && request.status == 200) {
      if (request.responseText) {
        callbackFunction(request.responseText);
      }
    }
  };
  request.send(vars);
}